When an object is placed at 2.0 m in front of a diverging lens, a virtual image is formed at 30 cm in front of the lens. What are the focal length of the lens and the lateral magnification of the image?
Answer to relevant QuestionsAn object 4.0 cm tall is in front of a converging lens of focal length 22 cm. The object is 15 cm away from the lens. (a) Use a ray diagram to determine whether the image is (1) real or virtual, (2) upright or inverted, and ...A small dog sits 3.0 m in front of a plane mirror. (a) Where is the dog’s image in relation to the mirror? (b) If the dog jumps at the mirror at a speed of 1.0 m/s, how fast does the dog approach its image? Using Fig. 23.28, derive (a) The thin lens equation and (b) The magnification equation for a thin lens. Two converging lenses L1 and L2 have focal lengths of 30 cm and 20 cm, respectively. The lenses are placed 60 cm apart along the same axis, and an object is placed 50 cm from L1 (110 cm from L2). Where is the image formed ...A biconvex lens is made of glass whose index of refraction is 1.6. The lens has a radius of curvature of 30 cm for one surface and 40 cm for the other. Calculate the focal length of this lens as used in air and under water.
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