# Question

When the excited electron in a hydrogen atom falls from n = 5 to n = 2, a photon of blue light is emitted. If an excited electron in He1 falls from n = 4, which energy level must it fall to so that a similar blue light (as with hydrogen) is emitted? Prove it.

## Answer to relevant Questions

The treatment of a particle in a one-dimensional box can be extended to a two-dimensional box of dimensions Lx and Ly yielding the following expression for energy: The two quantum numbers independently can assume only ...Assume that we are in another universe with different physical laws. Electrons in this universe are described by four quantum numbers with meanings similar to those we use. We will call these quantum numbers p, q, r, and s. ...An atom of a particular element is traveling at 1% of the speed of light. The de Broglie wavelength is found to be 3.31 × 10-3 pm. Which element is this? An excited hydrogen atom emits light with a wavelength of 397.2 nm to reach the energy level for which n = 2. In which principal quantum level did the electron begin? Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with n = 5 in a one-dimensional box 40.0 pm in length.Post your question

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