You have a concentration cell with Cu electrodes and Cu2
You have a concentration cell with Cu electrodes and [Cu2+] = 1.00 M (right side) and 1.0 × 1024 M (left side).
a. Calculate the potential for this cell at 25oC.
b. The Cu21 ion reacts with NH3 to form Cu(NH3)42+, where the stepwise formation constants are K1 = 1.0 × 103, K2 = 1.0 × 104, K3 = 1.0 × 103, and K4 = 1.0 × 103. Calculate the new cell potential after enough NH3 is added to the left cell compartment such that at equilibrium [NH3] = 2.0 M.
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