From the following data, determine f Ho for diborane, B2H6 (g), at 298 K: (I) B2H6 (g)
Question:
(I) B2H6 (g) + 3 O2 (g) → B2O3(s) + 3 H20 (g) ∆t Ho=-1941 kJ mol-1
(2) 2 B(s) + t Oh) → B2O3(S)
∆t, Ho = -2368 kJ mol-1
(3) H2 (g) + + 02(g) → H2O (g)
∆t, Ho = -241.8 kJ mol-1
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