Given the following data: Ca(s) + 2C(graphite) CaC2(s) H = 62.8 kJ Ca(s) + O2(g)
Question:
Ca(s) + 2C(graphite) → CaC2(s) ΔH = –62.8 kJ
Ca(s) + ½ O2(g) → CaO(s) ΔH = –635.5 kJ
CaO(s) + H2O(l) → Ca(OH)2(aq) ΔH = –653.1 kJ
C2H2(g) + 5/2 O2(g) → 2CO2(g) 1 H2O(l) ΔH = –1300 kJ
C(graphite) + O2(g) → CO2(g) ΔH = –393.5 kJ
Calculate ΔH for the reaction CaC2(s) + 2H2O(l) → Ca(OH) 2(aq) + C2H2(g)
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CaC 2 Ca 2 C H 628 kJ CaO H 2 O CaOH 2 H 6531 kJ 2 ...View the full answer
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