If R is a Dedekind domain with quotient field K, F is a finite dimensional extension field
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If R is a Dedekind domain with quotient field K, F is a finite dimensional extension field of K and Sis the integral closure of R in F (that is, the ring of all elements of F that are integral over R), then S is a Dedekind domain.
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To prove that the integral closure S of a Dedekind domain R in a finitedimensional extension field F of its quotient field K is itself a Dedekind doma...View the full answer
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Related Book For
Algebra Graduate Texts In Mathematics 73
ISBN: 9780387905181
8th Edition
Authors: Thomas W. Hungerford
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