A countercurrent system with three equilibrium stages is to be used for water-acetic acid-isopropyl ether extraction (see Table 13-7). Feed is \(40 \mathrm{wt} \%\) acetic acid and \(60 \mathrm{wt} \%\) water. Feed flow rate is \(2000 \mathrm{~kg} / \mathrm{h}\). Solvent added contains \(1 \mathrm{wt} \%\) acetic acid but no water. We desire a 5 \(\mathrm{wt} \%\) acetic acid raffinate. What solvent flow rate is required? What are flow rates of \(\mathrm{E}_{\mathrm{N}}\) and \(\mathrm{R}_{1}\) ?

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TABLE 13-7. Equilibrium data for water-acetic acid-isopropyl ether at 20C and 1 atm Water Layer, weight % Isopropyl Ether Layer, weight % Acetic Acid Water Isopropyl Ether Acetic Acid Water Isopropyl Ether XD XS YA YD ys 0.69 98.1 1.2 0.18 0.5 99.3 1.41 97.1 1.5 0.37 0.7 98.9 2.89 95.5 1.6 0.79 0.8 98.4 6.42 91.7 1.9 1.93 1.0 97.1 13.30 84.4 2.3 4.82 1.9 93.3 25.50 71.1 3.4. 11.40 3.9 84.7 36.70 58.9 4.4 21.60 6.9 71.5 44.30 45.1 10.6 31.10 10.8 58.1 46.40 37.1 16.5 36.20 15.1 48.7