Water at (60^{circ} mathrm{C}) and 0.95 bar is evaporating into a (12.0 mathrm{~cm}-1) ong tube (also at

Question:

Water at \(60^{\circ} \mathrm{C}\) and 0.95 bar is evaporating into a \(12.0 \mathrm{~cm}-1\) ong tube (also at \(60^{\circ} \mathrm{C}\) ) and diffusing through a stagnant layer of air. The device is illustrated in Figure 15-2.

a. Calculate the flux of water vapor if convection is included.

b. Calculate the value of the molar reference velocity.

c. If the tube is \(1.5 \mathrm{~cm}\) in diameter, calculate the grams of water evaporated per hour.

d. Calculate flux of water vapor if convection is not included (a calculation that is expected to be incorrect for this example).

Data: At \(60^{\circ} \mathrm{C}, D_{\text {water-air }}=3.05 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}, \mathrm{VP}_{\text {water }}=149.5 \mathrm{~mm} \mathrm{Hg}\)

Figure 15-2

image text in transcribed

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: