The ethyl mercaptan concentration in a mixture was determined by shaking a 1.795-g sample with 50.00 mL
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The ethyl mercaptan concentration in a mixture was determined by shaking a 1.795-g sample with 50.00 mL of 0.01204 M I2 in a tightly stoppered flask:
The excess I2 was back-titrated with 15.21 mL of 0.01437 M Na2S2O3. Calculate the percentage of C2H5SH (62.13 g/mol).
Transcribed Image Text:
2C₂H5SH + 1₂ →→C₂H5SSC₂H, +21¯ + 2H+
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Solution The percemt of C2H5SH in the mixture can be calcul...View the full answer
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Related Book For
Fundamentals Of Analytical Chemistry
ISBN: 9780357450390
10th Edition
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
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