Figure Q2(a) shows an active filter circuit. Vi R= 10k CH= 0.1 F 46 -1 (1)...
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Figure Q2(a) shows an active filter circuit. Vi R₁= 10k CH= 0.1 μF 46 -1 (1) RE190KQ +9V A -9V RH=10kQ R₂= 10kn R₁= 10kn C₁=0.002 μF T RF2=90k +9V -9V Figure Q2(a) Calculate the overall effective gain of the circuit in decibels. ㅗ Vo (6 marks) Determine the lower cut-off frequency and upper cut-off frequency. (6 marks) Figure Q2(a) shows an active filter circuit. Vi R₁= 10k CH= 0.1 μF 46 -1 (1) RE190KQ +9V A -9V RH=10kQ R₂= 10kn R₁= 10kn C₁=0.002 μF T RF2=90k +9V -9V Figure Q2(a) Calculate the overall effective gain of the circuit in decibels. ㅗ Vo (6 marks) Determine the lower cut-off frequency and upper cut-off frequency. (6 marks)
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Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
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