An unknown sample of Ni 2+ gave a current of 2.36 A in an electrochemical analysis. When
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An unknown sample of Ni2+ gave a current of 2.36 µA in an electrochemical analysis. When 0.500 mL of solution containing 0.028 7 M Ni2+ was added to 25.0 mL of unknown, the current increased to 3.79 µA.
(a) Denoting the initial, unknown concentration as [Ni2+]i, write an expression for the final concentration, [Ni2+]f, after 25.0 mL of unknown were mixed with 0.500 mL of standard. Use the dilution factor for this calculation.
(b) In a similar manner, write the final concentration of added standard Ni2+, designated as [S]f.
(c) Find [Ni2+]i in the unknown.
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