5. The ball leaves the ground at angle = 60. Determine the initial velocity if the...
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5. The ball leaves the ground at angle = 60. Determine the initial velocity if the ball is to just 0 clear the 3-m tall fence. Use g = 9.8 m/s. Note: to keep thing simple, you may assume h = 3 is enough to clear the fence. It should have been a bit higher. 6 m 3 m 1. Turn in: An object travels along the path defined by the vector function = (cos 2t)i+(sin 3t)j where t is time in seconds. a) Fort between 0,2, clearly draw the graph of this trajectory. If you do not have a printer, clearly reproduce the graph by hand. b) Determine the positions of the object at t=5 sec and at t= 6 sec. Then use arrows to clear show the direction of motion from t=5 sec tot 6 sec on your graph. I 2. Turn in: Use GeoGebra (or a 3-D graphing tool of your choice) to draw the space curve r(t)=(e)i+(sin 31)j+(10/7)k for 0t10 If you do not have a printer, clearly reproduce the graph by hand. 3. Turn in: Find the equation for the tangent line to the curve defined by the vector-valued function: r(t)=(sint, 3e, e) at the point (1)=(0,3,1). You can express the equation in parametric or symmetric form. 4. Turn in: Given the vector function r'(t) = (1) = ( 2 1+1)+(e^ ) j + (11) k k with the initial conditions (0)=(0,0,1). Determine (t) = f(t)dt. 5. The ball leaves the ground at angle = 60. Determine the initial velocity if the ball is to just 0 clear the 3-m tall fence. Use g = 9.8 m/s. Note: to keep thing simple, you may assume h = 3 is enough to clear the fence. It should have been a bit higher. 6 m 3 m 1. Turn in: An object travels along the path defined by the vector function = (cos 2t)i+(sin 3t)j where t is time in seconds. a) Fort between 0,2, clearly draw the graph of this trajectory. If you do not have a printer, clearly reproduce the graph by hand. b) Determine the positions of the object at t=5 sec and at t= 6 sec. Then use arrows to clear show the direction of motion from t=5 sec tot 6 sec on your graph. I 2. Turn in: Use GeoGebra (or a 3-D graphing tool of your choice) to draw the space curve r(t)=(e)i+(sin 31)j+(10/7)k for 0t10 If you do not have a printer, clearly reproduce the graph by hand. 3. Turn in: Find the equation for the tangent line to the curve defined by the vector-valued function: r(t)=(sint, 3e, e) at the point (1)=(0,3,1). You can express the equation in parametric or symmetric form. 4. Turn in: Given the vector function r'(t) = (1) = ( 2 1+1)+(e^ ) j + (11) k k with the initial conditions (0)=(0,0,1). Determine (t) = f(t)dt.
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