A flux-cored arc-welding (FCAW) process is used to join twolow-alloy steel plates at a 90° angle. The joint is an outsidefillet weld. The plates are 1?4-in thick. The weld bead consists of55% metal from the electrode and 45% from the steel plates. Theheat transfer factor for FCAW = 0.9, and the melting factor = 0.65.Welding current = 120 amps, and voltage = 20 volts. Velocity of thewelding head = 25 in/min. Electrode wire diameter = 0.125 in. Acore of flux (compounds that do not become part of the weld bead)runs through the center of the electrode. The diameter of the core= 0.0625 in. (a) What is the cross-sectional area of the weld bead?(b) How fast must the electrode wire be fed into the weldingoperation?

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To calculate the crosssectional area of the weld bead and the feed rate of the electrode wire we nee... View the full answer