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If a ball is thrown upward at 64 feet per second from a height of 4 feet, the height of the ball can be

If a ball is thrown upward at 64 feet per second from a height of 4 feet, the height of the ball can be modeled by S = 4+64t-16t2 feet, where t is the number of seconds after the ball is thrown. How long after the ball is thrown is the height 64 feet? It takes seconds for the ball to reach the height 64 feet. (Type an integer or a simplified fraction. Use a comma to separate answers as needed.)

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