Verify the characters in Table 6.3 for the irreducible representation 5 which has basis functions which
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Verify the characters in Table 6.3 for the irreducible representation Γ5 which has basis functions which are the three components of a vector in real space along x, y, and z, by explicitly constructing a matrix representation for one operator in each class.
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E T₁ T₂ 1 T3 2 Table 6.3 The character table of the Ta cubic symmetry double group Ē 8C3 8C3 3C₂ 654 654 60 Basis functions 302 654 6S4 60d 1 1 2 T4 3 3 T5 3 3 T6 2 -2 T7 2 -2 T8 4 T 1 1 - 1 0 0 1 1 -1 1 - 1 0 0 -1 1 1 1 2 1 0 0 0 1 -1 0 1 -1 -√√2 √2 0 0 220 - 1 1 -1 -1 00 0 1 -1 1 0 0 16 × 2 0 R= x² + y² + z² Lx LyLz (2z²2²-x² - y²), √3(x² - y²) Lx, Ly, Lz x, y, z 1/2,-1/2, 1/2,1/2 3/2,-3/2, 3/2,-1/2, $3/2,1/2, 3/2,3/2
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T5 is threedimensional with the basis functions x y and z Therefore the identity operator is 1 0 0 0 ...View the full answer
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