A metal, M, was converted to the chloride, MCl2. Then a solution of the chloride was treated

Question:

A metal, M, was converted to the chloride, MCl2. Then a solution of the chloride was treated with silver nitrate to give silver chloride crystals, which were filtered from the solution.
MCl2(aq) + 2AgNO3(aq) → M(NO3)2(aq) + 2AgCl(s)
If 2.434 g of the metal gave 7.964 g of silver chloride, what is the atomic weight of the metal? What is the metal?