A metal, M, was converted to the sulfate,M2(SO4)3. Then a solution of the sulfate was treated with

Question:

A metal, M, was converted to the sulfate,M2(SO4)3. Then a solution of the sulfate was treated with barium chloride to give barium sulfate crystals, which were filtered off.
M2(SO4)3(aq) + 3BaCl2(aq) → 2MCl3(aq) + 3BaSO4(s)
If 1.200 g of the metal gave 6.026 g of barium sulfate, what is the atomic weight of the metal? What is the metal?