A sample of aluminum sulfate 18-hydrate, Al2(SO4)318H2O, containing 159.3 mg is dissolved in 1.000 L of solution.
Question:
a. The molarity of Al2(SO4)3.
b. The molarity of SO42.
c. The molality of Al2(SO4)3, assuming that the density of the solution is 1.00 g/mL.
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Calculate the moles of Al 2 SO 4 3 18H 2 O using its molar mass of 66646 gmol and use this to calc...View the full answer
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