At least 25 g of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication.

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At least 25 μg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2. How many moles of THC does this 25 μg represent? How many molecules?

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Chemistry The Central Science

ISBN: 978-0321696724

12th edition

Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward

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Question Posted: Apr 19, 2016 06:48 AM

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At least 25 g of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication.

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25 10 6 g C 21 H 30 ...View the full answer

Chemistry The Central Science

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