Draw a graph, similar to Figure 3-11, of the torsional energy of 2-methylbutane as it rotates about
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Figure 3-11
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3.8 kJ (0.9 kcal) 15 kJ 21 kJ (3.6 kcal) (5 kcal) -21 kJ (5 kcal) 3.8 kJ (0.9 kcal) 120° 15 kJ (3.6 kcal) 180 lowest 15 kJ (3.6 kcal) 3.8 kJ (0.9 kcal) 360 -21 kJ (5 kcal) totally eclipsed totally eclipsed gauche eclipsed ant eclipsed gauche 120 CH3 H НН 2-40
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Relative energies on the graph on the next page were calculated using these values from the text 38 ...View the full answer
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