Question: Drosophila females heterozygous for three recessive mutations, a, b, and c, were crossed to males homozygous for all three mutations. The cross yielded the following
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Construct a linkage map showing the correct order of these genes and estimate the distances between them.
Phenotype Number 75 +++ 348 +bc 96 110 a ++ ab+ 306 abc 65
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From the parental classes c and a b the heterozygous females must have ha... View full answer

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