For the system ethyl ethunoale (1) in-heptane(2) at 343.15 K, lnyj = Q.95x; Inyj =055*J.

Question:

For the system ethyl ethunoale (1) in-heptane(2) at 343.15 K,
• lnyj = Q.95x; Inyj =055*J.
• P1sat = 79.80 kPa P2sat = 40.50 kPa,
Assuming the validity of Eq. (10.5).
(a) Make a BUBL P calculation for T = 343.15 x1 = 0.05.
(A) Make a DEW P calculation for T = 343.15 K. y1 = 0.05,
(c) What is the azeotrope composition and pressure at T = 343.15 K?
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Introduction to Chemical Engineering Thermodynamics

ISBN: 978-0071247085

7th edition

Authors: J. M. Smith, H. C. Van Ness, M. M. Abbott

Question Posted: