In a meeting of mimes, mime 1 goes through a displacement d1 = (4.0 m)i + (5.0

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In a meeting of mimes, mime 1 goes through a displacement d1 = (4.0 m)i + (5.0 m)j and mime 2 goes through a displacement d2 = (– 3.0 m)i + (4.0 m)i. What are?

(a) d1 x d2

(b) d1 ∙ d2

(d) The component of d1 along the direction of d2?

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Fundamentals of Physics

ISBN: 978-0471758013

8th Extended edition

Authors: Jearl Walker, Halliday Resnick

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Question Posted: Nov 23, 2010 11:43 PM

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In a meeting of mimes, mime 1 goes through a displacement d1 = (4.0 m)i + (5.0

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The two vectors are written as in unit of meters d 4050 dd d3040dd a The vector cross prod...View the full answer

Fundamentals of Physics

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