Photolysis of Cr (CO)6 in the presence of certain molecules M, can give rise to the following
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Suppose that the absorbed light intensity is so weak that! «k4 [Cr (CO) 5M]. Find the factor fin the equation d [Cr(CO)5M]/dt=-f[Cr(CO)5M]. Show that a graph of l/f against [M] should be a straight line.
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(1) Cr(CO), +hv→ CríCO), +CO (2) Cr(CO); + CO -→Cr(CO), (3) Cr(CO), + M→ Cr(CO),M (4) Cr(CO),M Cr(CO), + M
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dCrCOs dr 1 kCrCOCO k3 CrCO5M k4CrCOM 0 steady state Ik4CrCOM k CO ...View the full answer
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