A point charge of +5.00 C is located on the x-axis at x = 4.00 m, next
Question:
(a) Calculate the magnitude of the electric field at x = 3.00 m.
(b) Calculate the magnitude of the electric field at x = -3.00 m.
(c) According to Gauss's law, the net flux through the sphere is zero because it contains no charge. Yet the field due to the external charge is much stronger on the near side of the sphere (i.e., at x = 3.00 m) than on the far side (at x = -3.00 m). How, then, can the flux into the sphere (on the near side) equal the flux out of it (on the far side)? Explain. A sketch will help.
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Related Book For
University Physics with Modern Physics
ISBN: 978-0321501219
12th Edition
Authors: Hugh D. Young, Roger A. Freedman, Lewis Ford
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