Generalizing Exercise 51, let S be any subset of a group G. a. Show that H s
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Generalizing Exercise 51, let S be any subset of a group G.
a. Show that Hs = {x ∈ G| xs = sx for all s ∈ S} is a subgroup of G.
b. In reference to part (a), the subgroup HG is the center of G. Show that HG is an abelian group.
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a Closure Let x y H S Then xs sx and ys sy for all s S We then have xys xys xsy xsy sxy sxy for al...View the full answer
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