We saw in Corollary 23 .17 that the cyclotomic polynomial s irreducible over Q for every prime

Question:

We saw in Corollary 23 .17 that the cyclotomic polynomial 

s irreducible over Q for every prime p. Let ζ be a zero of ∅p(x), and consider the field Q(ζ).
a. Show that ζ, ζ2 , · · · , ζp-1 are distinct zeros of ∅p(x), and conclude that they are all the zeros of ∅p(x).
b. Deduce from Corollary 48.5 and part (a) of this exercise that G(Q(ζ)/Q) is abelian of order p - 1.
c. Show that the fixed field of G(Q(ζ)/Q) is Q. 


Data from Corollary 48.5

Let α be algebraic over a field F. Every isomorphism ψ mapping F(α) onto a subfield of F̅ such that ψ(a) = a for a ∈ F maps α onto a conjugate β of α over F. Conversely, for each conjugate β of α over F, there exists exactly one isomorphism ψα,β of F(α) onto a subfield of F̅ mapping α onto β and mapping each a ∈ F onto itself.


Proof Let ψ be an isomorphism of F(α) onto a subfield of F̅ such that ψ(a) = a for a ∈ F. Let irr(α, F) = a0 + a₁x + + anxn. Then a0 + a1α + · · ·anαn = 0, so 0 ψ(a0 + a1α + · · ·anα)= a0 +a1ψ(α) +· · · + anψ(α)n, and β = ψ(α) is a conjugate of α. 


Conversely, for each conjugate β of α over F, the conjugation isomorphism ψα,βof Theorem 48.3 is an isomorphism with the desired properties. That ψα,β is the only such isomorphism follows from the fact that an isomorphism of F(α) is completely determined by its values on elements of F and its value on α.

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