Find a general solution. Determine the kind and stability of the critical point. y' 1 = -3y
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Find a general solution. Determine the kind and stability of the critical point.
y'1 = -3y1 - 2y2
y'2 = -2y1 - 3y2
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Px 3x1 y2 2y1 323 PY 45y075 125y2 The critical point is at y0 45 and y1 125 ...View the full answer
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