A plane traveling horizontally at 80 m s over flat ground at an elevation of 3000 m releases an emergency packet The trajectory of the packet is given by x 80t, y 4 9t 2 3000, for t 0, where the origin is the point on the ground directly beneath the plane at the moment of the release Graph the traj...

The packages lands when y 0 so we see ...

A plane traveling horizontally at 80 m/s over flat ground at an elevation of 3000 m releases

Question:

A plane traveling horizontally at 80 m/s over flat ground at an elevation of 3000 m releases an emergency packet. The trajectory of the packet is given by

x = 80t, y = -4.9t² + 3000, for t ≥ 0,

where the origin is the point on the ground directly beneath the plane at the moment of the release. Graph the trajectory of the packet and find the coordinates of the point where the packet lands.

ул 80 m/s 3000 m х