Consider a pendulum of length L meters swinging only under the influence of gravity. Suppose the pendulum

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Consider a pendulum of length L meters swinging only under the influence of gravity. Suppose the pendulum starts swinging with an initial displacement of θ0 radians (see figure). The period (time to complete one full cycle) is given by

п/2 do T = VI - k² sin² o

where ω2 = g/L, g ≈ 9.8 m/s2 is the acceleration due to gravity, and k2 = sin20/2). Assume L = 9.8 m, which means ω = 1 s-1.

Consider a pendulum of length L meters swinging only under


a. Use a computer algebra system to find the period of the pendulum for θ0 = 0.1, 0.2,. . ., 0.9, 1.0 rad.

b. For small values of θ0, the period should be approximately 2π seconds. For what values of θ0 are your computed values within 10% of 2π (relative error less than 0.1)?

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Related Book For  answer-question

Calculus Early Transcendentals

ISBN: 978-0321947345

2nd edition

Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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