Given A = 6a x + 3a y + 2a z , the projection of A
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Given A = – 6ax + 3ay + 2az, the projection of A along ay is
(a) –12
(b) –4
(c) 3
(d) 7
(e) 12
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The answer is c 3 Projection of a vector A along another vector B ...View the full answer
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