The radiation efficiency is given by eq. (13.50) as where P rad is the radiation power and
Question:
The radiation efficiency is given by eq. (13.50) as
where Prad is the radiation power and Pohm is the power loss due to ohmic resistance of the antenna. For a cylindrical conductor of length Δz that carries current I,
where
and δ is the skin depth. A short antenna of length Δz has an efficiency of 20%. Assume that the efficiency is improved by increasing the length to 2Δz, while keeping the same current. What is the new efficiency?
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Step by Step Answer:
Let P rad1 and P rad2 be the old and new radiated powers respectively Let ...View the full answer
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