Two components in an HPLC separation have retention times that differ by 22 s. The first peak
Question:
Two components in an HPLC separation have retention times that differ by 22 s. The first peak elutes in 10.5 minutes, and the peak widths are approximately equal. The void time, tM, was 63 s. Use a spreadsheet to find the minimum number of theoretical plates needed to achieve the following resolution, Rs, value 0.50, 0.75, 0.90, 1.0, 1.10, 1.25, 1.50, 1.75, 2.0, and 2.5.
How would the results change if peak 2 were twice as broad as peak 1?
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Step by Step Answer:
The retention time of peak 2 is equal to 2tM 2tMR2 where tM and ...View the full answer
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Related Book For 
Fundamentals Of Analytical Chemistry
ISBN: 9780357450390
10th Edition
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
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