Professor Narcissus claims that if a relation R is symmetric and transitive, then it is also reflexive.
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Professor Narcissus claims that if a relation R is symmetric and transitive, then it is also reflexive. He offers the following proof. By symmetry, a R b implies b R a. Transitivity, therefore, implies a R a. Is the professor correct?
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Related Book For
Introduction to Algorithms
ISBN: 978-0262033848
3rd edition
Authors: Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest
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