Professor Narcissus claims that if a relation R is symmetric and transitive, then it is also reflexive.

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Professor Narcissus claims that if a relation R is symmetric and transitive, then it is also reflexive. He offers the following proof. By symmetry, a R b implies b R a. Transitivity, therefore, implies a R a. Is the professor correct?

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Related Book For  answer-question

Introduction to Algorithms

ISBN: 978-0262033848

3rd edition

Authors: Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest

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