Calculate the lifetimes of U 238 and Po 212 , using Equations 9.26 and 9.29. The energy

Question:

Calculate the lifetimes of U238 and Po212, using Equations 9.26 and 9.29.

The energy of the emitted alpha particle can be deduced by using Einstein’s formula (E = mc2):

where mp is the mass of the parent nucleus, md is the mass of the daughter nucleus, and m is the mass of the alpha particle (which is to say, the He4 nucleus). To figure out what the daughter nucleus is, note that the alpha particle carries off two protons and two neutrons, so Z decreases by 2 and A by 4. Look up the relevant nuclear masses. To estimate v, use E = (1/2) mv2; this ignores the (negative) potential energy inside the nucleus, and surely underestimates v, but it’s about the best we can do at this stage. Incidentally, the experimental lifetimes are 6x109 yrs and 0.5 μs, respectively.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Introduction To Quantum Mechanics

ISBN: 9781107189638

3rd Edition

Authors: David J. Griffiths, Darrell F. Schroeter

Question Posted: