Calculate H o R at 675 K for the reaction 4NH 3 (g) + 6NO(g) 5N
Question:
Calculate ΔHoR at 675 K for the reaction 4NH3(g) + 6NO(g) → 5N2(g) + 6H2O(g) using the temperature dependence of the heat capacities from the data tables. Compare your result with ΔHoR at 298.15 K. Is the difference large or small? Why?
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
14400 08086 1878 7374 kJ mol 1 380 kJ mol 1 H o R 29815 K 5H o f N 2 g 6H o f H 2 ...View the full answer
Answered By
Ayush Mishra
I am a certified online tutor, with more than 3 years of experience in online tutoring. My tutoring subjects include: Physics, Mathematics and Mechanical engineering. I have also been awarded as best tutor for year 2019 in my previous organisation. Being a Mechanical Engineer, I love to tell the application of the concepts of science and mathematics in the real world. This help students to develop interest and makes learning fun and easy. This in turn, automatically improves their grades in the subject. I teach students to get prepared for college entry level exam. I also use to teach undergraduate students and guide them through their career aim.
2+ Reviews
10+ Question Solved
Related Book For 
Question Posted:
