The vapor pressure of methanol(l) is 16 94 10 3 Pa at 298 15 K Use this value to calculate G o f (CH 3 OH, g) G o f (CH 3 OH, l) Compare your result with those in Table 4 1 ...

From the tables G o f C 2 H 5 OH g G o f C 2 H 5 OH l 1623 kJ ...

The vapor pressure of methanol(l) is 16.94 10 3 Pa at 298.15 K. Use this value

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The vapor pressure of methanol(l) is 16.94 × 10³ Pa at 298.15 K. Use this value to calculate ΔG^o_f (CH₃OH, g) − ΔG^o_f (CH₃OH, l). Compare your result with those in Table 4.1.

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Physical Chemistry

ISBN: 978-0321812001

3rd edition

Authors: Thomas Engel, Philip Reid

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Question Posted: Apr 30, 2018 12:59 AM

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The vapor pressure of methanol(l) is 16.94 10 3 Pa at 298.15 K. Use this value

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