Under anaerobic conditions, glucose is broken down in muscle tissue to form lactic acid according to the reaction C 6 H 12 O 6 (s) 2CH 3 CHOHCOOH(aq) Thermodynamic data at T 298 K for glucose and lactic acid are given in the following table Calculate Icirc G o R atT 298 K and T 310 K In your calcul...

a b AHR 29815 K 2AH lactic acid A ...

Under anaerobic conditions, glucose is broken down in muscle tissue to form lactic acid according to the

Question:

Under anaerobic conditions, glucose is broken down in muscle tissue to form lactic acid according to the reaction: C₆H₁₂O₆(s) †’ 2CH₃CHOHCOOH(aq). Thermodynamic data at T = 298 K for glucose and lactic acid are given in the following table.

Cp(JK-- mol!) s°(J K-l mol-1) AH; (kJ mol) Glucose (s) Lactic Acid (aq) 209.2 219.2 -1273.1 -673.6 127.6 192.1

Calculate Î”G^o_R atT = 298 K and T = 310.K. In your calculation at 310. K,

a. Assume that Î”H^o_R and Î”S^o_R are constant in this temperature interval

b. Calculate Î”H^o_R and Î”S^o_R at 310. K using the data in the previous table. Assume all heat capacities are constant in this temperature interval.