A proton moving in a uniform magnetic field with v 1 = 1.00 10 6 i

Question:

A proton moving in a uniform magnetic field with v1 = 1.00 × 106 î m/s experiences force F1 = 1.20 × 10-16 k̂ N. A second proton with v2 = 2.00 × 106 ĵ m/s experiences F2 = -4.16 × 10-16 k̂ N in the same field. What is B? Give your answer as a magnitude and an angle measured ccw from the +x-axis.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: