Find an equation of the tangent to the curve at the point corresponding to the given value
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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter.
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Vt, y = t? – 2t; t= 4
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1 dy x t y t 2t t4 dx 2t 2 dt 1 2t x y 28 ...View the full answer
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