If f and t are twice differentiable functions, show that 2 (fg) = f 2 g
Question:
If f and t are twice differentiable functions, show that
∇2(fg) = f∇2g + g∇2f + 2∇f • ∇g
Transcribed Image Text:
v°(fg) = fV°g + gV²f + 2Vf • Vg
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