Solve the system of equations using the method of substitution or the method of elimination. If the
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Solve the system of equations using the method of substitution or the method of elimination. If the system has no solution, say that it is inconsistent.
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2х — 4у + z%3D —15 х+ 2у — 4г %3 5х — бу — 2z %3D -3 27
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2x4yz 15 x2y4z 27 5x6y2z3 Multiply the first equation by 1 and the ...View the full answer
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