Over a small wavelength range, the refractive index of a certain material varies approximately linearly with wavelength
Question:
Over a small wavelength range, the refractive index of a certain material varies approximately linearly with wavelength as n(λ) = na + nb(λ − λa), where na, nb and λa are constants, and where λ is the free-space wavelength.
(a) Show that d/dω = −(2πc/ω2)d/dλ.
(b) Using β(λ) = 2πn/λ, determine the wavelength-dependent (or independent) group delay over a unit distance.
(c) Determine β2 from your result of part (b).
(d) Discuss the implications of these results, if any, on pulse broadening.
Step by Step Answer:
a With as the free space wavelength we use 2c from which dd 2c 2 Then dd dd ...View the full answer
Related Video
Using a few basic physics principles, you can impress your friends with a trick that makes a bottle disappear. For this experiment, you will need a mini plastic bottle, glycerin, a glass, and a funnel. First, open the bottle and pour some glycerin into it, then close the bottle tightly. Next, pour some water into the glass using a funnel. Place the mini bottle into the glass of water and it will look normal. This is because light travels through air faster than it travels through the glass and water, allowing our eyes to see the bottle inside the glass. However, when you fill the mini bottle with more glycerin, and pour glycerin into the glass, then put the glycerin filled bottle into the glass with glycerin in it. Half of the bottle that is submerged in the glycerin will become invisible as the light travels through glass and glycerin at the same speed, thus it does not bend and no refraction takes place, making the bottle invisible. This happens because both glass and glycerin have almost the same refractive index, which causes the speed of light to be the same in both mediums, causing no bending of light and making the bottle disappear.
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