The following cell has a voltage of 0.083 V: Hg(l) | Hg(NO3)2(0.001 0 M), KI(0.500 M)

Question:

The following cell has a voltage of 0.083 V:

Hg(l) | ƒ Hg(NO3)2(0.001 0 M), KI(0.500 M) || S.H.E.

From this voltage, calculate the equilibrium constant for the reaction

In 0.5 M KI, virtually all the mercury is present as HgI²₄^-.

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Quantitative Chemical Analysis

ISBN: 978-1429218153

8th edition

Authors: Daniel C. Harris

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Question Posted: Jun 11, 2020 10:06 AM

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The following cell has a voltage of 0.083 V: Hg(l) | Hg(NO3)2(0.001 0 M), KI(0.500 M)

Question:

Hg²+ + 41 = Hgl?

Step by Step Answer:

The Nernst equation Therefore equilibrium constant for rea...View the full answer

Quantitative Chemical Analysis

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