A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. The stone is launched 50.0 m above the ground, and the stone just misses the edge of the roof on the way down.
1. Using t = 0 s as the time the stone leaves the thrower's hand at position, determine the time at which the stone reaches its maximum height.
2. Find the maximum height of the stone

3. Determine the velocity of the stone when it returns to the height from which it was thrown

4. Find the position of the stone at t = 5.00 s

Answer rating: 100% (QA)

Considering the upward direction as negative and downward as positive 1 At maximum height the veloci... View the full answer