1)

Pyridine, C5H5N, is a weak base and reacts with HCL as follows
C5H5N(aq) + HCL(aq) = C5H5NH+(aq) + CL-(aq)
what is the PH of a 0.015M solution of the pyridinium ion (C5H5NH+)? The Kb for Pyridine is .0000000016. (hint: calculate the Ka for pyridinium ion and use it in the calculation.)

2). Aniline is a weak organic base with the formular C6H5NH2. The anilinium ion has the formulaC6H5NH3+ and its Ka = 0.000023. a) write the chemical reaction showing the hydrolysis of the anilinium ion. b) calculate the PH of a 0.0400M solution of anilinium chloride.