# 10:24 PM 0.0KB/s ll Vo LTE 23 19-09-2020_Jr.Sup.. Sri

## Expert Answer

No answer yet for this question.

10:24 PM 0.0KB/s ll Vo LTE 23 19-09-2020_Jr.Sup.. Sri Chaitanya IIT Academy 27. 19-09-2020 Jr.Super60(In Com)_Jee-Main_UTM-06_Q.P A cubic block of mass m and side length b is placed on a smooth floor. A smooth and rigid rod of length L and with negligible mass is leaning against the block. A sphere of mass M is attached to the upper end of the rod. The lower end of the rod is fixed at point – 0, but the rod can rotate freely around the point within the | vertical plane. Initially the angle between the rod and the floor is a while the system is at rest. After releasing, find the speed of the block when the angle between the rod and the floor is B MgL(sina - sin B) 1)b, mb? + ML' sin“ B 2MgL(sina - sin ß) 2)b, mb? + ML' sin“ B MgL(sina – sin ß) mb? + ML? cos“ ß 2MgL(sin a - sin B) 3)ь, mb? + ML cos*B 28. Precession is the result of the angular velocity of rotation (spin) and the angular velocity produced by the torque. It is an angular velocity about a line that makes an angle 0 with the permanent rotation axis. In the diagram, a top of mass m is performing precession motion. The torque due to gravitational force causes a change in the angular momentum L in the direction of that torque causing the top to process with angular velocity o, which is given by: (Given r is distance of COM from point of rotation 'P'. I, & o, are the moment of inertia and angular velocity of top about spin axis respectively) Given (@, >> m,) Sec: Jr.Super60 Space for Rough Work Page 7 Sri Chaitanya IIT Academy 19-09-2020_Jr.Super60(In Com)_Jee-Main_UTM-O6_Q.P Precession axis L Spin axis