1.3 y 3.1 3 x-3 f1(x)=- 2-x-18 15 -0.1 A student recognizes that x = 9...

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1.3 y 3.1 3 √x-3 f1(x)=- 2-x-18 15 -0.1 A student recognizes that x = 9 will cause the denominator to be zero in the given function. What, if anything, does this tell you about the limit as x->9 ? The limit as x->9 can be found with the graph, tables, and (or) algebraic techniques. The limit as x->9 is automatically "DNE," because we are not allowed to have 0 in the denominator. When x = 9, the numerator is also zero. This gives us, for which the limit as x->9 is automatically "DNE" 1.3 y 3.1 3 √x-3 f1(x)=- 2-x-18 15 -0.1 A student recognizes that x = 9 will cause the denominator to be zero in the given function. What, if anything, does this tell you about the limit as x->9 ? The limit as x->9 can be found with the graph, tables, and (or) algebraic techniques. The limit as x->9 is automatically "DNE," because we are not allowed to have 0 in the denominator. When x = 9, the numerator is also zero. This gives us, for which the limit as x->9 is automatically "DNE"

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Given filxx3 at x9 2x18 fix form which is indetermi... View the full answer