Show that the solution of: dy +2= sin(2x) y) = 2 with initial condition, %3D %3D...
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Show that the solution of: dy +2= sin(2x) y) = 2 with initial condition, %3D %3D dx is 4xy = sin(2x) – 2x cos(2x) + 2n -1. Show that the solution of: dy +2= sin(2x) y) = 2 with initial condition, %3D %3D dx is 4xy = sin(2x) – 2x cos(2x) + 2n -1.
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13 so1h dx dre x Given that dy s sin 2x A first order linear ODE has the ... View the full answer
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