7. A concrete slab, 300 mm thick, 5 m wide and 10 m long, is used...

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7. A concrete slab, 300 mm thick, 5 m wide and 10 m long, is used to support a live load of 3 kN/m² on one half and 5kN/m² on the other half of the slab as shown in Figure 2. The concrete slab is supported by three equally loaded steel 200×500×10RHS (rectangular hollow section) beams, each 10 m long. Assume the three beams carry equal load. Take density of concrete = 24 kN/m³, and density of steel = 7850kg/m3 %3D %3D =18-5/6N/n? V Live load = 3 kN/m2 Live load = 5 kN/m² 200 mm 5 m 500 mms 1300 mm steel beam- Cross-section 5 m 5 m Wall thickness = 10mm Figure 2 (a) Calculate the dead load (G) on each steel beam (including self-weight), in kN/m. (Ans: 13.07KN/m) Step Task Value Cross-sectional area of concrete slab 1 ×'s こ 20'3=8:3} supported by single beam (m?) = &U é be 16-67 Weight of concrete slab per beam (kN/m) = Cross-sectional area of each steel 0-2 x 0-5 beam (m²) = %3D Self-weight of each steel beam 24/x/0-1 78.5x6"/ (kN/m) = %3D Total weight on one beam (slab + %3D beam self-weight) (kN/m) = -> -> 2. 3. 4- (b) Calculate the live loads (Q) on each steel beam, in kN/m. (Ans: 5 & 8.3kN/m) Step Task Value Width of plan area acting on beam 1 (m) = %3D Live load on beam right hand side KN m2 X (kN/m) = Live load on beam left hand side kN 3メ (kN/m) = %3D (c) Calculate the ultimate limit state load each steel beam, in kN/m. (Ans: 23.2 & 28.2kN/m) Step Task Value ULS load on right hand side of beam 1 12.DL t 1-5L (kN/m) = ULS load on left hand side of beam 12-DL + 1-5レL (kN/m) = %3| (d) Assume the lines below represents a single beam. Show the dead loads, live loads and ULS loads on the beam and all relevant dimensions. Dead Loads for Live Loads for ULS Loads for (e) A 2m high 'temporary' divider wall weighing 90kg/m length is now installed on the slab running from point A to B. How will this load appear on each beam? Add this load to the diagrams in part (d) above. 2. 3. 2. 7. A concrete slab, 300 mm thick, 5 m wide and 10 m long, is used to support a live load of 3 kN/m² on one half and 5kN/m² on the other half of the slab as shown in Figure 2. The concrete slab is supported by three equally loaded steel 200×500×10RHS (rectangular hollow section) beams, each 10 m long. Assume the three beams carry equal load. Take density of concrete = 24 kN/m³, and density of steel = 7850kg/m3 %3D %3D =18-5/6N/n? V Live load = 3 kN/m2 Live load = 5 kN/m² 200 mm 5 m 500 mms 1300 mm steel beam- Cross-section 5 m 5 m Wall thickness = 10mm Figure 2 (a) Calculate the dead load (G) on each steel beam (including self-weight), in kN/m. (Ans: 13.07KN/m) Step Task Value Cross-sectional area of concrete slab 1 ×'s こ 20'3=8:3} supported by single beam (m?) = &U é be 16-67 Weight of concrete slab per beam (kN/m) = Cross-sectional area of each steel 0-2 x 0-5 beam (m²) = %3D Self-weight of each steel beam 24/x/0-1 78.5x6"/ (kN/m) = %3D Total weight on one beam (slab + %3D beam self-weight) (kN/m) = -> -> 2. 3. 4- (b) Calculate the live loads (Q) on each steel beam, in kN/m. (Ans: 5 & 8.3kN/m) Step Task Value Width of plan area acting on beam 1 (m) = %3D Live load on beam right hand side KN m2 X (kN/m) = Live load on beam left hand side kN 3メ (kN/m) = %3D (c) Calculate the ultimate limit state load each steel beam, in kN/m. (Ans: 23.2 & 28.2kN/m) Step Task Value ULS load on right hand side of beam 1 12.DL t 1-5L (kN/m) = ULS load on left hand side of beam 12-DL + 1-5レL (kN/m) = %3| (d) Assume the lines below represents a single beam. Show the dead loads, live loads and ULS loads on the beam and all relevant dimensions. Dead Loads for Live Loads for ULS Loads for (e) A 2m high 'temporary' divider wall weighing 90kg/m length is now installed on the slab running from point A to B. How will this load appear on each beam? Add this load to the diagrams in part (d) above. 2. 3. 2.

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